Different models of batteries are mixed, or the hazards of the same model of new and old batteries are very large. Different batteries are different because of the different internal electrolytes, the corresponding internal resistance and potentials will be different. When using them, if it is series, it may cause an internal resistance, low potential to excessively placement, and the amount of energy is depleted, and the internal current exceeds the allowable value, rapidly aging, and scrapped. At this time, new batteries in the battery pack will also be dragged and generate a chain reaction. If it is concurrent, the internal circulation of the battery pack is generated. On the one hand, the external output is weakened, and the other hand may cause the battery itself and even explosion. Even if you emerged, don't mix the battery of the internal electrolyte. For example, charging batteries and alkaline batteries are dangerous.Disadvantages of new and old battery mix
The battery is old. Due to a series of chemical reasons, the electric might will have a slight decline, the internal resistance will increase significantly, such a battery is mixed with the new battery, a lot of drawbacks. Now in a new battery (E1 = 1.5V, R = 1ω) With an old battery (E2 = 1.4V, R2 = 5ωMixed, give a 3V / 3W light to power for example as an analysis:
If two batteries are powered in series.
R1 = 3ω(Lamp load resistance)
When the new battery is supplied, the current is I1.
I1 = 0.375A
When the new old battery is connected in series, the current is I2,
I2 = 0.322A, indicating that the mixed battery is small, and the voltage dropped in the old battery internal resistance to VR2, VR2 = R2•I2 = 5×0.322 = 1.61V> E2, it indicates that the old battery contribution to the circuit is smaller than its consumption, which is the new old battery string light, often the brightness of the light is darker.
In parallel with two batteries, there is shown in Figure 2, which is based on the law of Kirhof:
I1 = (R1 + RL) + I2RL = E1
I2 = (R2 + RL) + I1RL = E2:
4i1 + 3i2 = 1.53i1 + 8i2 = 1.4 available:
I1 = 0.339A I2 = 0.048A
IL = i1 + i2 = 0.387A
The above data indication, when the new and old parallel power is powered, the current supplied from the old battery is very small, and the current through the lamp is much smaller than the new battery (0.387A-0.375A = 0.012a), more serious is, once stopped For external power, ie disconnect the electric bond K, the second battery self-cultivation, the new battery will supply power to the old battery, its current is I.
I = 0.017a, that is, there is a 20mA equivalent self-discharge current, calculated when the battery capacity is 3A, the discharge time is T, T = 176h = 7 days, that is, the new battery will be exhausted after a week. In short, the new and old battery is mixed, regardless of the series or parallel, the shortcomings are much, so the new and old batteries should not be mixed. Recommend: LiFePO4 Battery Manufacturer Energy storage battery Manufacturer Integrated machine energy storage battery series Manufacturer Lead lithium battery Manufacturer Outdoor Backup Battery Manufacturer Portable outdoor power supply Manufacturer Power battery Manufacturer Powerwall LiFePO4 Battery Manufacturer Battery rack Manufacturers Telecom LiFePO4 Battery Manufacturer Wall mounted battery storage Manufacturer China Lifepo4 Battery
